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-4.9x^2+15x+25=0
a = -4.9; b = 15; c = +25;
Δ = b2-4ac
Δ = 152-4·(-4.9)·25
Δ = 715
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{715}}{2*-4.9}=\frac{-15-\sqrt{715}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{715}}{2*-4.9}=\frac{-15+\sqrt{715}}{-9.8} $
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